Break and Continue

Break and Continue Statement : 

  • Break Statement is used to interrupt the loop execution.
  • On the occurence of break statement execution control of a program directly comes out of loop by skipping next loop execution and continues with a statement following a loop.
  • Syntax : break;
  • Example : Let's consider following block of code
#include<stdio.h>
int main()
{
   int i;
   for(i=1;i<=100;i++)
    {
         pritf(" %d ",i);
         if(i==50)
           break;
      }
   return 0;
}

Output :
1 2 3 4 5 ..... 50
  • Here though for loop written for printing 100 natural numbers it will print only 50 numbers because of break statement. 

  • Continue Statement : Continue statement continues with the next iteration of loop by skipping statements following it inside the loop.
  • Syntax : continue;
  • Example : Let's see following block of code
#include<stdio.h>
int main()
{
   int i;
   for(i=1;i<=100;i++)
   {
       if(i%2==0)
          continue;
       printf("%d",i);
    }
 return 0;
}

Output :
1 3 5 7 9 ...... 99
  • Here program will print only odd numbers between 1 to 100 because of continue statement. 

Comments

Post a Comment

Please do not enter any spam link in message.

Popular posts from this blog

Write a program to allocate memory dynamically for n integers. Accept the elements and calculate their sum and average

C File=> /* Write a program to allocate memory dynamically for n integers. Accept the elements and calculate their sum and average. */ #include<stdio.h> #include<stdlib.h> int main() {     int n,i,sum=0;     int *ptr;     float avg;     printf("\n Enter how many integers: ");     scanf("%d",&n);     ptr=(int*)malloc(n*sizeof(int));     for(i=0;i<n;i++)   {       printf("\n Enter number%d : ",i+1);       scanf("%d",&ptr[i]);       sum=sum+ptr[i];   }   avg=sum/n;   printf("\n Sum of numbers = %d\n",sum);   printf(" Average of numbers = %f",avg);   return 0 ; }
Read more

C program to accept names of n cities and search for city named “Pune”.

C File => /* Write a C program to accept names of n cities and search for city named “Pune” */ #include<stdio.h> #include<string.h> #include<stdlib.h> int main() {      int n,flag=0,i;      char str[50][50];      printf("\n Enter how many strings? ");      scanf("%d",&n);      for(i=0;i<n;i++)     {          printf("\n Enter String%d : ",i+1);          scanf("%s",str[i]);     }     for(i=0;i<n;i++)    {        if(strcmp(str[i],"Pune")==0)       {           flag=1;           break;        }    }    if(flag==1)       printf("\n Pune is found..");    else       printf("\n Pune NOT found..");    return 0; }
Read more